TSTP Solution File: SYN996^1 by Satallax---3.5

View Problem - Process Solution

%------------------------------------------------------------------------------
% File     : Satallax---3.5
% Problem  : SYN996^1 : TPTP v8.1.0. Released v3.7.0.
% Transfm  : none
% Format   : tptp:raw
% Command  : satallax -E eprover-ho -P picomus -M modes -p tstp -t %d %s

% Computer : n015.cluster.edu
% Model    : x86_64 x86_64
% CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 2.10GHz
% Memory   : 8042.1875MB
% OS       : Linux 3.10.0-693.el7.x86_64
% CPULimit : 300s
% WCLimit  : 600s
% DateTime : Thu Jul 21 11:47:37 EDT 2022

% Result   : Theorem 2.32s 2.49s
% Output   : Proof 2.32s
% Verified : 
% SZS Type : -

% Comments : 
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%----WARNING: Could not form TPTP format derivation
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%----ORIGINAL SYSTEM OUTPUT
% 0.00/0.12  % Problem  : SYN996^1 : TPTP v8.1.0. Released v3.7.0.
% 0.13/0.13  % Command  : satallax -E eprover-ho -P picomus -M modes -p tstp -t %d %s
% 0.13/0.34  % Computer : n015.cluster.edu
% 0.13/0.34  % Model    : x86_64 x86_64
% 0.13/0.34  % CPU      : Intel(R) Xeon(R) CPU E5-2620 v4 @ 2.10GHz
% 0.13/0.34  % Memory   : 8042.1875MB
% 0.13/0.34  % OS       : Linux 3.10.0-693.el7.x86_64
% 0.13/0.34  % CPULimit : 300
% 0.13/0.34  % WCLimit  : 600
% 0.13/0.34  % DateTime : Tue Jul 12 01:56:25 EDT 2022
% 0.20/0.34  % CPUTime  : 
% 2.32/2.49  % SZS status Theorem
% 2.32/2.49  % Mode: mode506
% 2.32/2.49  % Inferences: 591
% 2.32/2.49  % SZS output start Proof
% 2.32/2.49  thf(conj,conjecture,((![X1:$i]:(~((![X2:$i]:(~(((r @ X1) @ X2))))))) => (~((![X1:$i>$i]:(~((![X2:$i]:((r @ X2) @ (X1 @ X2)))))))))).
% 2.32/2.49  thf(h0,negated_conjecture,(~(((![X1:$i]:(~((![X2:$i]:(~(((r @ X1) @ X2))))))) => (~((![X1:$i>$i]:(~((![X2:$i]:((r @ X2) @ (X1 @ X2))))))))))),inference(assume_negation,[status(cth)],[conj])).
% 2.32/2.49  thf(ax1080, axiom, ~(p1), file('<stdin>', ax1080)).
% 2.32/2.49  thf(pax3, axiom, (p3=>![X3:$i > $i]:~(![X2:$i]:fr @ X2 @ (X3 @ X2))), file('<stdin>', pax3)).
% 2.32/2.49  thf(ax1078, axiom, (p1|p3), file('<stdin>', ax1078)).
% 2.32/2.49  thf(nax1, axiom, (p1<=(![X6:$i]:~(![X2:$i]:~(fr @ X6 @ X2))=>~(![X7:$i > $i]:~(![X2:$i]:fr @ X2 @ (X7 @ X2))))), file('<stdin>', nax1)).
% 2.32/2.49  thf(c_0_4, plain, ~p1, inference(fof_simplification,[status(thm)],[ax1080])).
% 2.32/2.49  thf(c_0_5, plain, ![X520:$i > $i]:(~p3|~fr @ (esk257_1 @ X520) @ (X520 @ (esk257_1 @ X520))), inference(shift_quantors,[status(thm)],[inference(skolemize,[status(esa)],[inference(variable_rename,[status(thm)],[inference(fof_nnf,[status(thm)],[pax3])])])])).
% 2.32/2.49  thf(c_0_6, plain, (p1|p3), inference(split_conjunct,[status(thm)],[ax1078])).
% 2.32/2.49  thf(c_0_7, plain, ~p1, inference(split_conjunct,[status(thm)],[c_0_4])).
% 2.32/2.49  thf(c_0_8, plain, ![X532:$i, X534:$i > $i]:((fr @ X532 @ (esk263_1 @ X532)|p1)&(~fr @ (esk264_1 @ X534) @ (X534 @ (esk264_1 @ X534))|p1)), inference(distribute,[status(thm)],[inference(shift_quantors,[status(thm)],[inference(skolemize,[status(esa)],[inference(variable_rename,[status(thm)],[inference(fof_nnf,[status(thm)],[inference(fof_simplification,[status(thm)],[nax1])])])])])])).
% 2.32/2.49  thf(c_0_9, plain, ![X3:$i > $i]:(~p3|~fr @ (esk257_1 @ X3) @ (X3 @ (esk257_1 @ X3))), inference(split_conjunct,[status(thm)],[c_0_5])).
% 2.32/2.49  thf(c_0_10, plain, p3, inference(sr,[status(thm)],[c_0_6, c_0_7])).
% 2.32/2.49  thf(c_0_11, plain, ![X1:$i]:(fr @ X1 @ (esk263_1 @ X1)|p1), inference(split_conjunct,[status(thm)],[c_0_8])).
% 2.32/2.49  thf(c_0_12, plain, ![X3:$i > $i]:~fr @ (esk257_1 @ X3) @ (X3 @ (esk257_1 @ X3)), inference(cn,[status(thm)],[inference(rw,[status(thm)],[c_0_9, c_0_10])])).
% 2.32/2.49  thf(c_0_13, plain, ![X1:$i]:fr @ X1 @ (esk263_1 @ X1), inference(sr,[status(thm)],[c_0_11, c_0_7])).
% 2.32/2.49  thf(c_0_14, plain, ($false), inference(spm,[status(thm)],[c_0_12, c_0_13]), ['proof']).
% 2.32/2.49  thf(1,plain,$false,inference(eprover,[status(thm),assumptions([h0])],[])).
% 2.32/2.49  thf(0,theorem,((![X1:$i]:(~((![X2:$i]:(~(((r @ X1) @ X2))))))) => (~((![X1:$i>$i]:(~((![X2:$i]:((r @ X2) @ (X1 @ X2))))))))),inference(contra,[status(thm),contra(discharge,[h0])],[1,h0])).
% 2.32/2.49  % SZS output end Proof
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